java迭代问题,二次迭代问题i

代码工厂 其他问答 1
import java.util.Iterator;
import java.util.NoSuchElementException;

public class MyArrrayList implements Iterable {
private static final int DEFAULT_CAPACITY = 10;
private int theSize;
private AnyType[] theItems;

public MyArrrayList() {
    clear();
}

public void clear() {
    theSize = 0;
    ensureCapality(DEFAULT_CAPACITY);
}

public int size() {
    return theSize;
}

public boolean isEmpty() {
    return size() == 0;
}

public void trimSize() {
    ensureCapality(size());
}

public AnyType get(int idx) {
    if (idx < 0 || idx >= size())
        throw new ArrayIndexOutOfBoundsException();
    return theItems[idx];
}

public AnyType set(int idx, AnyType newVal) {
    if (idx < 0 || idx >= size())
        throw new ArrayIndexOutOfBoundsException();
    AnyType old = theItems[idx];
    theItems[idx] = newVal;
    return old;
}

@SuppressWarnings("unchecked")
public void ensureCapality(int newCapality) {
    if (newCapality < theSize)
        return;
    AnyType[] old = theItems;
    theItems = (AnyType[]) new Object[newCapality];
    for (int i = 0; i < size(); i++) {
        theItems[i] = old[i];
    }
}

public boolean add(AnyType x) {
    add(size(), x);
    return true;
}

public void add(int idx, AnyType x) {
    if (theItems.length == size())
        ensureCapality(size() * 2 + 1);
    for (int i = theSize; i > idx; i--)
        theItems[i] = theItems[i - 1];
    theItems[idx] = x;
    theSize++;
}

public AnyType remove(int idx) {
    if (idx < 0 || idx >= size())
        throw new ArrayIndexOutOfBoundsException();
    AnyType removeItem = theItems[idx];
    for (int i = idx; i < theSize; i++)
        theItems[i] = theItems[i + 1];
    theSize--;
    return removeItem;
}

@Override
public Iterator<AnyType> iterator() {
    // TODO Auto-generated method stub
    return new ArrayListIterator(this);
}

private static class ArrayListIterator<AnyType> implements Iterator<AnyType> {
    private int current = 0;
    private MyArrrayList<AnyType> theList;
    public ArrayListIterator(MyArrrayList<AnyType> list){
        theList=list;
    }

    public boolean hasNext() {
        return current < theList.size();
    }

    public AnyType next() {

        return theList.theItems[current++];
    }

    public void remove() {
        theList.remove(--current);
    }
}

public static void main(String[] args) {
    MyArrrayList<Integer> list=new MyArrrayList<Integer>();
    for(int i=1;i<20;i++)
    list.add(i);

    Iterator<Integer> it=list.iterator();
    while(it.hasNext())
    {
        System.out.print(it.next());
        System.out.print(" ");

    }
    Iterator<Integer> its=list.iterator();


    while(it.hasNext())
    {
        System.out.println(it.next());
    }


}
}

请问我的输出为:1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 明明写了两个输出语句,为什么只有一个输出呢?

回复

共2条回复 我来回复
  • 毕设小屋
    这个人很懒,什么都没有留下~
    评论

    先用it.hasNext() 判断集合里是不是已经没有元素了, 如果有就用it.next();就是取得当前集合的元素 然后把指针往后移一位指向下一个元素(java确实还是有指针的只不过你不能自己调用罢了) 指针指完了就没有了,所以后面就进不去了,如果你还想打印可改为 it =list.iterator(); while(it.hasNext()) { System.out.println(it.next()); }

    0条评论
  • 源码项目助手
    这个人很懒,什么都没有留下~
    评论
    Iterator its=list.iterator();
    
    while(it.hasNext())
    {
        System.out.println(it.next());
    }
    

    第二个你参数写错了,应该是its.hasNext() 。

    0条评论

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